2 batsman(Batsman A and Batsman B) are on 94 Runs...
2 balls remaining in the last over...
7 runs to win...
Last Wicket...
Both batsman make 100 & win the match..... How?
Post your answers in comments section... All the Best!
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Here is the Answer!!!
First ball, Batsman A on strike (94), 7 to win - batsmen hits the ball and takes three runs. However, on one of the runs, one of the batsmen accidentally fails to make his ground, so the umpire calls a short run and that run is disallowed. While the ball is still in play the fielder throws it to the wicket-keeper but overthrows it, and the ball goes to the boundary and so an additional four runs are awarded. Thus, six runs (3 runs - 1 short run + 4 overthrows = 6 Runs) are awarded to Batsman A for his century, Batsman B would now be on strike.
Second ball, Batsman B on strike (94), 1 to win -- the ball is struck over the boundary for six. Batsman B scores his century and his team wins the match.
This scenario also solves the raised issue.. two centuries and the match winning..
Hats Off to one of my Colleague(Mr.Yugendran) who guessed almost correct!
7 comments:
Batsman A hit a single and Batsman B hit a Six. They got the win score of 7 runs and totally they made 101 from 94.
Dear above Anonymous.. Seems you have misunderstood the question.. Both Batsman should get 100. As per your answer only Batsman B getting 100 and not the Batsman A.
Hi i didn't misunderstand the question. I was trying to say both together got 100 and win the game. Have you taken my answer has a serious one lol
Deo, Where are you Man? I couldn't see any comments from you recently here
Hey.. I forgot to say something in my Last comment. I really appreciate the guy who is running this blog. He is doing some good works on this blog. Keep Rocking.. All the best!
Good Puzzle.
Hi Nancy,
I am here...But silent...
Regards
Deodar
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